Derive the relation between ∆G and ∆Stotal
soln:-
Gibb’s free energy G is defined as
G
= H - TS
Where H= enthalpy
of system
S= entropy of system
T= absorbed temp
G is state
function because H, T, S are state functions and extensive property.
The change in Gibb’s energy ∆G depends
upon the initial and final state and does not depend upon path
Therefore the
change on Gibb’s energy at const temp and pressure defined as
∆G
= ∆H - T∆S
Free energy change
= Total enthalpy change - Temp X (Total entropy change)
It is the energy which is measure
of work that can be obtained from a system at const temp and pressure.
Unit; - The SI unit
of ∆G is J or KJ (or J/mol/or KJ/mole)
The C.G.S unit of ∆G is cal or Kcal (Cal/mol or Kcal/mole)
The total entropy change for a
system and its surrounding for the process is given by.
∆Stotal = ∆Ssystem + ∆S surr.
∆S total = ∆S + ∆S (surr)
By
second law of thermodynamics’ for spontaneous process
∆S total > 0
If + ∆H is the entropy increases for
the process or reaction at const. temp (T) and pressure then enthalpy decreases
for surrounding will be -∆H
∆S (surr) = - ∆H /T
∆S = ∆S system + ∆S surr
∆S total = ∆S system - ∆H /T
T
∆S total = T ∆S system - ∆H
-T
∆S total = ∆H - T ∆S system
------------- 1
By
Gibb’s equation
∆G = ∆H - T∆S total
-------------------2
Comparing
above two equation
∆G
= -T ∆S total
This
equation indicate that ∆G and ∆S total are have opposite signs because T is
always positive.
∆G
increases and ∆S total decreases
Signification of ∆G
i) ∆G < 0 process is spontaneous
ii) ∆G > 0 process is non - spontaneous
iii) ∆G = 0 process
is at equilibrium
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